l^2+3l-130=0

Solution for l^2+3l-130=0 equation:

Simplifying
l2 + 3l + -130 = 0

Reorder the terms:
-130 + 3l + l2 = 0

Solving
-130 + 3l + l2 = 0

Solving for variable 'l'.

Factor a trinomial.
(-13 + -1l)(10 + -1l) = 0

Subproblem 1
Set the factor '(-13 + -1l)' equal to zero and attempt to solve:

Simplifying
-13 + -1l = 0

Solving
-13 + -1l = 0

Move all terms containing l to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + -1l = 0 + 13

Combine like terms: -13 + 13 = 0
0 + -1l = 0 + 13
-1l = 0 + 13

Combine like terms: 0 + 13 = 13
-1l = 13

Divide each side by '-1'.
l = -13

Simplifying
l = -13
Subproblem 2
Set the factor '(10 + -1l)' equal to zero and attempt to solve:

Simplifying
10 + -1l = 0

Solving
10 + -1l = 0

Move all terms containing l to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1l = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1l = 0 + -10
-1l = 0 + -10

Combine like terms: 0 + -10 = -10
-1l = -10

Divide each side by '-1'.
l = 10

Simplifying
l = 10
Solution
l = {-13, 10}